Answer:
(i)
Given a * b = a ? Here
a ? b may or may not
For
example,
Let
5 ? 7 = ?2
is not a
binary operation on Z+.
(ii)
Given a * b =
Since
for every a,
, there exists
a unique element
therefore
& is a binary operation on Z+.
(iii) Given
a * b =
Here
Hence
* is a binary operation on R.
(iv) Given
a * b = |a ? b|
Here
is a binary
operation on Z+.
(v) Given
a * b
Here
is a binary
operation on Z+.
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