Answer:
Let
f(x) = x and g(x) = |x|
g(?x)
= |?x| = |x|
is not
one-one i.e. injective.
Also,
gof :
Let
x1 : x2 be two elements of N such that (gof) (x1)
=
(gof ) (x2)
g(f(x1))
= g(f(x2))
g(x1)
= g(x2)
|x1|
= |x2|
x1
= x2
is injective.
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