of
a 1.5 V cell. The balance point of the cell in open circuit is 76.3 cm. When a
resistor of 9.5 
is used in
the external circuit of the cell, the balance point shifts to 64.8 cm length of
the potentiometer wire. Determine the internal resistance of the cell.
Answer:
Here, 
Where
l1 = 76.3 cm;
l2
= 64.8 cm
and
R = 8.4 
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