12th Class Physics Electro Magnetic Induction

  • question_answer 41)
      ODBAC is a fixed rectangular conductor of negligible resistance (CO is not connected) and OP is a conductor which rotates clockwise with an angular velocity , Fig. 4(EP).13. The entire system is in a uniform magnetic field B whose direction is along the normal to the surface of the rectangular conductor ABDC. The conductor OP is in electric contact with ABDC. The rotating conductor has a resistance of  per unit length. Find the current in the rotating conductor, as it rotates by 180.    

    Answer:

                      The set up is shown in Fig. 4(EP).14. Between time t = 0 and t = , the rod OP will make contact with side BD. At any time t : 0 < t < , let the length OQ of contact be .  Magnetic flux through the area ODQ is                                                                                                  where Magnitude of emf generated, If R is resistance of the rod in contact, then induced current Now,    For t =  to t = , the rod is in contact with the side AB, as shown in Fig. 4(EP). 15. Let the length of the rod in contact, OQ = . Magnetic flux linked with area ODBQ = B x area of trapezium ODBQ  where Magnitude of emf generated, Induced current, For , t =   to  t =  the rod is in contact with the side AC as shown in Fig. 4(EP).16. Let the length of the rod in contact OQ = .                        Magnetic flux linked with area ODBAQ                                                                           Magnitude of induced emf, Induced current,


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