Answer:
Let the potential
be zero at O, then
VA
+ VB = 0,
where
is electric
potential due to charge and is the electric
potential due to charge .
i.e.
i.e.
i.e.
i.e.
5(0.16 ? x) = 3x
i.e.
0.8 = 3x + 5x = ?8x
or
x = 0.1 m = 10 cm.
Now
taking the second case i.e. when
x2
= 0.16 + x, we have
or
i.e.
5x = 3x ? 0.8
i.e.
x = 0.4 m = 0.4 × 100 = 40 cm.
i.e.
electric potential is also zero at a distance of 40 cm from the charge q1.
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