12th Class Physics blank

  • question_answer 35)
      Consider a wire carrying a steady current,  placed in a uniform magnetic field perpendicular to its length. Consider the charges inside the wire. It is known that magnetic forces do not work. This implies that (a) motion of charges inside the conductor is unaffected by  since they do not absorb energy (b) Some charges inside the wire move to the surface as a result of (c) if the wire moves under the influence of , no work is done by the force (d) if the wire moves under the influence of , no work is done by the magnetic force on the ions, assumed fixed within the wire

    Answer:

      (b,d)(a) Motion of charges inside the conductor is affected by magnetic field , due to magnetic force  given by (b) Due to magnetic force, some charges inside the wire move to the surface of wire.               (c) The force on wire of length , carrying current when subjected to magnetic field is,   = . It acts perpendicular to the plane containing and  and is directed as given by Right Hand rule. If the wire moves under the influence of  at an angle , where 90°, then work done, W = Fs cos , can not be zero. (d) When wire moves under the influence of , then displacement of the ions is perpendicular to the magnetic force . Therefore work done is zero.


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