Answer:
The initial mechanical energy E of the two
deutrons before collision is given by E = 2 K.E.
(K.E. = kinetic
energy)
When the two
deutrons stop, their energy is totally potential energy U given by
Using
law of conservation of energy,
2 K.E.
K.E.
But
K.E.
Coulomb
barrier
= 180000 eV=
180 ke V
P.E. = 2K.E. = 180 x
2 = 360 keV.
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