question_answer 27)

  Truth table for the given circuit (Fig. 9(EP).6) is           (a) 

A	B	E
0	0	1
0	1	0
1	0	1
1	1	0

                        (b) 

A	B	E
0	0	1
0	1	0
1	0	0
1	1	0

                  (C) 

A	B	E
0	0	0
0	1	1
1	0	0
1	1	1

                  (d)

A	B	E
0	0	0
0	1	1
1	0	1
1	1	0

 

Answer:

  (c) In circuit, C = A.B and D = .B E=C+D=(A.B)+( .B) The truth table of this arrangement of gates will be as given below :

A	B		C=A.B	d=.B	E=(C+D)
0	0	1	0	0	0
0	1	1	0	1	1
1	0	0	0	0	0
1	1	0	1	0	1