Answer:
(b,c,d) From the given
transfer characteristics of a base biased common emitter transistor, we note
that
(i) When Vi
= 0.4 V, there is no collector current. The transistor circuit is m cut off
state.
(ii)
When Vi = 1 V (which is inbetween 0-6 V to 2 V), the transistor
circuit is in active state and is used as an
amplifier.
(iii)
When yi = 0.5 V, there is no collector current. The transistor is in
cut off state. The transistor circuit can be used as a switch turned
off.
(iv) When Vi
= 2.5 V, the collector current becomes maximum and transistor is in saturation
state and can be used as switch turned on state. Thus, options (b, c and d) are
true.
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