Player | Game 1 | Game 2 | Game 3 | Game 4 |
A | 14 | 16 | 10 | 10 |
B | 0 | 8 | 6 | 4 |
C | 8 | 11 | Did not play | 13 |
Answer:
(i) \[\text{Mean =}\frac{\text{sum of all observations}}{\text{number of obsesvations}}\] \[=\frac{14+16+10+10}{4}=\frac{50}{4}=12.5\] So, A's average number of points scored per game is 12.5. (ii) To find the mean number of points per game for C, we shall divide the total points by 3 because the number of games under consideration is 4 but 'C' did not play game 3. (iii) \[\text{Mean =}\frac{\text{sum of all observations}}{\text{number of obsesvations}}\] \[=\frac{0+8+6+4}{4}=\frac{18}{4}=4.5\] (iv) C's average number of points scored per game \[\text{=}\frac{\text{sum of all observations}}{\text{number of observations}}\] \[=\frac{8+11+13}{3}=\frac{32}{3}=10.6\] [\[\because \] ?C? did not play Game 3] So, the best performer is A.
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