Answer:
(a) We have, \[93mm=93\times \frac{1}{10}cm=\frac{93}{10}cm=9.3cm\] [\[1000m=1km\]HCF of 60 and 100 = 20] (b) We have, \[\therefore \] [\[1m=\frac{1}{1000}km=0.001km\]HCF of 5 and 100 = 5] (c) We have, \[\frac{1}{1000}\] [\[\frac{1}{10}\]HCF of 75 and 100 = 25] (d) We have, \[\frac{11}{5}=\frac{11\times 2}{5\times 2}\] [\[=\frac{22}{10}=2.2\]HCF of 18 and 100 = 2] (e) We have, \[1.2=\frac{12}{10}=\frac{6}{5}\] [\[\frac{1}{100}\]HCF of 25 and 100 = 25] (f) We have, \[\left( \frac{1}{100} \right).\] [\[\frac{1}{10}.\]HCF of 125 and 1000 = 125] (g) We have,\[\therefore \] [\[\frac{1}{100}=\]HCF of 66 and 1000 = 2]
You need to login to perform this action.
You will be redirected in
3 sec