Answer:
Let it take \[x\] hours. We have the following table.
Lesser the speed, more the number of hours to reach the destination. So, this is a case of inverse proportion. Hence, \[60\times 2=80\times x\] \[\Rightarrow \] \[x=\frac{60\times 2}{80}\] \[\Rightarrow \] \[x=\frac{3}{2}=1\frac{1}{2}\] Thus, \[1\frac{1}{2}\] hours would be taken. Speed (in km/h) 60 80 Number of hours 2 \[x\]
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