Answer:
(i) \[{{x}^{2}}+xy+8x+8y\] \[{{x}^{2}}+xy+8x+8y\] \[=x(x+y)+8(x+y)\] \[=(x+y)(x+8)\] |Taking \[(x+y)\]common (ii) \[15xy-6x+5y-2\] \[15xy-6x+5y-2\] \[=3x(5y-2)\,+(5y-2)\] |Taking \[(5y-2)\] common (iii) \[ax+bx-ay-by\] \[ax+bx-ay-by\] \[=x(a+b)\,-y(a+b)\] \[=(a+b)\,(x-y)\] |Taking \[(a+b)\]common (iv) \[15pq+15+9q+25p\] \[15pq+15+9q+25p\] \[=15pq+9q+25p+15\] \[=3q(5p+3)\,+5(5p+3)\] \[=(5p+3)\,(3q+5)\] |Taking \[(5p+3)\]common (v) \[z-7+7xy-xyz\] \[z-7+7xy-xyz\] \[=z-7-xyz+7xy\] \[=1(z-7)\,-xy\,(z-7)\] \[=(z-7)\,(1-xy)\] |Taking \[(z-7)\]common
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