Answer:
(a) We have, \[=13>11>5>4>3>2\] [simplest form] (b) We have, \[\therefore \] [simplest form] (c) We have, \[=\frac{7}{13},\frac{7}{11},\frac{7}{5},\frac{7}{4},\frac{7}{3},\frac{7}{2}\] [simplest form] (d) We have, \[=\frac{7}{2},\frac{7}{3},\frac{7}{4},\frac{7}{5},\frac{7}{11},\frac{7}{13}\] [simplest form] (e) We have, \[\frac{12}{15}-\frac{7}{15}=\frac{12-7}{15}=\frac{5}{15}=\frac{1}{3}\] [simplest form] (f) We have, \[\frac{5}{8}+\frac{3}{8}=\frac{5+3}{8}=\frac{8}{8}=1\] [simplest form] (g) We have, \[1-\frac{2}{3}=\frac{3}{3}-\frac{2}{2}=\frac{3-2}{3}=\frac{1}{3}\] \[\frac{5}{6}\frac{2}{6},\] (h) We have, \[\frac{3}{6}0,\] [simplest form] (i) We have, \[\frac{1}{6}\frac{6}{6},\] \[\frac{8}{6}\frac{5}{6}\] \[=\frac{6}{8}\] [simplest form]
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