Answer:
Lateral surface area of the hollow cylinder \[=4224\,c{{m}^{2}}\] \[\Rightarrow \] Area of the rectangular sheet \[=4224\,c{{m}^{2}}\] \[\Rightarrow \] Length \[\times 33=4224\] \[\Rightarrow \] Length \[=\frac{4224}{33}\] \[\Rightarrow \] Length = 128 cm \[\therefore \] Perimeter of the rectangular sheet = 2(Length + Breadth) = 2(128 + 33) cm = 2(161) cm = 322 cm Hence, the perimeter of the rectangular sheet is 322 cm.
You need to login to perform this action.
You will be redirected in
3 sec