Answer:
For a cylindrical container Diameter of the base = 14 cm \[\therefore \] Radius of the base \[(r)=\frac{14}{2}\,cm\] Height (h) = 20 cm \[\therefore \] Curved surface area of the container \[=2\pi rh\] \[=2\times \frac{22}{7}\,\times 7\times 20\] \[=880\,c{{m}^{2}}\] \[\therefore \] Surface area of the label \[=880\,c{{m}^{2}}-2\left( 2\times \frac{22}{7}\,\times 7\times 2 \right)\,c{{m}^{2}}\] \[=880\,c{{m}^{2}}-176\,c{{m}^{2}}\] \[=704\,c{{m}^{2}}\] Hence, the surface area of the label is \[704\,\,c{{m}^{2}}\].
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