Answer:
(a) Area of the triangles \[\text{= }\frac{\text{1}}{\text{2}}\text{ }\!\!\times\!\!\text{ (base }\!\!\times\!\!\text{ height) = }\frac{\text{1}}{\text{2}}\text{ (4 }\!\!\times\!\!\text{ 3) c}{{\text{m}}^{\text{2}}}\text{= 6c}{{\text{m}}^{\text{2}}}\] (b) Area of the triangle \[\text{=}\frac{\text{1}}{\text{2}}\text{(base }\!\!\times\!\!\text{ height) = }\frac{\text{1}}{\text{2}}\text{ (5 }\!\!\times\!\!\text{ 3}\text{.2) = 8c}{{\text{m}}^{\text{2}}}\] (c) Area of the triangle \[\text{=}\frac{\text{1}}{\text{2}}\text{(base }\!\!\times\!\!\text{ height) = }\frac{\text{1}}{\text{2}}\text{ (3}\times \text{4) c}{{\text{m}}^{\text{2}}}\text{= 6c}{{\text{m}}^{\text{2}}}\] (d) Area of the triangle: \[\text{=}\frac{\text{1}}{\text{2}}\text{(base }\!\!\times\!\!\text{ height) = }\frac{\text{1}}{\text{2}}\text{ (3}\times 2\text{) c}{{\text{m}}^{\text{2}}}\text{= 3c}{{\text{m}}^{\text{2}}}\]
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