Answer:
Radius of inner circle \[=\text{19}-\text{1}0=\text{9 m}\] \[\therefore \] Circumference of the inner circle \[=2\pi r\] \[\text{= 2 }\!\!\times\!\!\text{ 3}\text{.14 }\!\!\times\!\!\text{ 9 m}\] \[\text{= 56}\text{.52 cm}\] Radius of the outer circle \[=\text{19 m}\] \[\therefore \] Circumference of the outer circle \[=2\pi r\] \[\text{= 2 }\!\!\times\!\!\text{ 3}\text{.14 }\!\!\times\!\!\text{ 19 m}\] \[\text{= 119}\text{.32 m}\]
You need to login to perform this action.
You will be redirected in
3 sec