Answer:
(i) Area of the whole lawn \[=l\times b=\text{10 m }\!\!\times\!\!\text{ 5m = 50 }{{\text{m}}^{\text{2}}}\] (ii) Diameter of the flower bed \[=\text{2 m}+\text{2 m}=\text{4 m}\] \[\Rightarrow \] Radius (r) of the flower bed \[=\text{2 m}\] Area of flower bed \[\text{= }\!\!\pi\!\!\text{ }{{\text{r}}^{\text{2}}}\text{= }\frac{\text{22}}{\text{7}}\text{ (2}{{\text{)}}^{\text{2}}}\text{ }{{\text{m}}^{\text{2}}}\text{ = }\frac{\text{88}}{\text{7}}{{\text{m}}^{\text{2}}}\text{ =12}\text{.57 }{{\text{m}}^{\text{2}}}\] (iii) Area of the lawn excluding the area of the flower bed = Area of the whole lawn - Area of flower bed \[\text{= 50 }{{\text{m}}^{\text{2}}}\text{-}\frac{\text{88}}{\text{7}}{{\text{m}}^{\text{2}}}\] \[\text{=}\left( \text{50 - }\frac{\text{88}}{\text{7}} \right){{\text{m}}^{\text{2}}}\text{=}\frac{\text{262}}{\text{7}}{{\text{m}}^{\text{2}}}\text{= 37}\text{.43 }{{\text{m}}^{\text{2}}}\] (iv) Circumference of the flower bed \[=2\pi r\] \[\text{= 2 }\!\!\times\!\!\text{ }\frac{\text{22}}{\text{7}}\text{ }\!\!\times\!\!\text{ 2m = }\frac{\text{88}}{\text{7}}{{\text{m}}^{\text{2}}}\text{ = 12}\text{.57}\]
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