question_answer 8)

Construct \[\Delta DEF\] such that DE = 5 cm, DF = 3 cm, and \[m\angle EDF=90{}^\circ \].

Answer:

                Steps of construction 1. Draw a line segment DE of length 5 cm. 2. At D, draw DX making \[\text{9}{{0}^{\text{o}}}\] with DE. 3. With D as centre, draw an arc of radius 3 cm. It cuts DX at the point F. 4. Join FE.                                                      \[\Delta DEF\] is now obtained.