Answer:
Construction: Produce BO to D such that BO = OD. Join AD and CD. Proof. \[\overline{AD}||\overline{BC}:\,\,\overline{AB}||\overline{DC}\]. So in parallelogram ABCD, the midpoint of the diagonal \[\overline{AC}\] is O. Hence, O is equidistant from A, B and C.
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