6th Class Mathematics Whole Numbers

  • question_answer 11)
    Find the value of the following. (a) 297 x 17 + 297 x 3 (b) 54279 x 92 + 8 x 54279 (c) 81265 x 169 ? 81265 x 69 (d) 3845 x 5 x 782 + 769 x 25 x 218

    Answer:

                    (a) We have, 297 x 17 + 297 x 3 = 297 x (17 + 3) = 297 x 20 = 5940 [taking 297 as a common term] (b) We have, 54279 x 92 + 8 x 54279 = 54279 x (92 + 8) [taking 54279 as a common term] = 54279 x 100 = 5427900 (c) We have, 81265 x 169 ? 81265 x 69 = 81265 x (169 ? 69) [Taking 81265 as a common term]         = 81265 x 100 = 8126500            (d) We have, 3845 x 5 x 782 + 769 x 25 x 218                                         = 3845 x 5 x 782 + (769 x 5) x 5 x 218                         [\[\because \]25 = 5 x 5]         = 3845 x 5 x 782 + 3845 x 5 x 218 = 3845 x 5 x (782 + 218) = 3845 x 5 x 1000 = 19225 x 1000 = 19225000


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