Homogeneous and Non-homogeneous Systems of Linear Equations
Category : JEE Main & Advanced
A system of equations \[AX=B\] is called a homogeneous system if \[B=O\]. If \[B\ne O\], it is called a non-homogeneous system of equations.
e.g., \[2x+5y=0\]
\[3x-2y=0\]
is a homogeneous system of linear equations whereas the system of equations given by
e.g., \[2x+3y=5\]
\[x+y=2\]
is a non-homogeneous system of linear equations.
(1) Solution of Non-homogeneous system of linear equations
(i) Matrix method : If \[AX=B\], then \[X={{A}^{-1}}B\] gives a unique solution, provided A is non-singular.
But if A is a singular matrix i.e., if \[|A|=0\], then the system of equation \[AX=B\] may be consistent with infinitely many solutions or it may be inconsistent.
(ii) Rank method for solution of Non-Homogeneous system \[AX=B\]
(a) Write down A, B
(b) Write the augmented matrix \[[A:B]\]
(c) Reduce the augmented matrix to Echelon form by using elementary row operations.
(d) Find the number of non-zero rows in A and \[[A:B]\] to find the ranks of A and \[[A:B]\] respectively.
(e) If \[\rho (A)\ne \rho (A:B),\] then the system is inconsistent.
(f) \[\rho (A)=\rho (A:B)=\] the number of unknowns, then the system has a unique solution.
If \[\rho (A)=\rho (A:B)<\] number of unknowns, then the system has an infinite number of solutions.
(2) Solutions of a homogeneous system of linear equations : Let \[AX=O\] be a homogeneous system of 3 linear equations in 3 unknowns.
(a) Write the given system of equations in the form \[AX=O\] and write A.
(b) Find \[|A|\].
(c) If \[|A|\ne 0\], then the system is consistent and \[x=y=z=0\] is the unique solution.
(d) If \[|A|=0\], then the systems of equations has infinitely many solutions. In order to find that put \[z=K\] (any real number) and solve any two equations for \[x\] and \[y\] so obtained with \[z=K\] give a solution of the given system of equations.
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