Rutherford's Nuclear Model

Category : JEE Main & Advanced

(1) Rutherford carried out experiment on the bombardment of thin (10?4 mm) Au foil with high speed positively charged \[\alpha -\]particles emitted from Ra and gave the following observations based on this experiment,

(i) Most of the \[\alpha -\] particles passed without any deflection.

(ii) Some of them were deflected away from their path.

(iii) Only a few (one in about 10,000) were returned back to their original direction of propagation.

                                 

(2) From the above observations he concluded that, an atom consists of

(i) Nucleus which is small in size but carries the entire mass i.e. contains all the neutrons and protons.

(ii) Extra nuclear part which contains electrons. This model was similar to the solar system.

(3) Properties of the nucleus

(i) Nucleus is a small, heavy, positively charged portion of the atom and located at the centre of the atom.

(ii) All the positive charge of atom (i.e. protons) are present in nucleus.

(iii) Nucleus contains neutrons and protons, and hence these particles collectively are also referred to as nucleons.           

(iv) The size of nucleus is measured in Fermi (1 Fermi = 10?13 cm).

(v) The radius of nucleus is of the order of \[1.5\times {{10}^{-13}}cm.\] to \[6.5\times {{10}^{-13}}cm.\] i.e. \[1.5\] to \[6.5\] Fermi. Generally the radius of the nucleus (\[{{r}_{n}})\] is given by the following relation,         

\[{{r}_{n}}={{r}_{o}}(=1.4\times {{10}^{-13}}cm)\times {{A}^{1/3}}\]          

This exhibited that nucleus is \[{{10}^{-5}}\] times small in size as compared to the total size of atom.

(vi) The Volume of the nucleus is about \[{{10}^{-39}}\]\[c{{m}^{3}}\] and that of atom is \[{{10}^{-24}}c{{m}^{3}},\] i.e., volume of the nucleus is \[{{10}^{-15}}\] times that of an atom.

(vii) The density of the nucleus is of the order of \[{{10}^{15}}g\,c{{m}^{-3}}\] or \[{{10}^{8}}\] tonnes \[c{{m}^{-3}}\] or \[{{10}^{12}}kg/cc\]. If nucleus is spherical than,

Density =\[\frac{\text{mass of the nucleus}}{\text{volume of the nucleus  }}=\]\[\frac{\text{mass number}}{6.023\times {{10}^{23}}\times \frac{4}{3}\pi {{r}^{3}}}\]

(4) Drawbacks of Rutherford's model

(i) It does not obey the Maxwell theory of electrodynamics, according to it ?A small charged particle moving around an oppositely charged centre continuously loses its energy?. If an electron does so, it should also continuously lose its energy and should set up spiral motion ultimately failing into the nucleus.

(ii) It could not explain the line spectra of \[H-\] atom and discontinuous spectrum nature.



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