question_answer

  A household uses the following electric appliances refrigerator of rating 400 W for 10 hours each day. (b) two electric fans of rating 80 W each for 6 hours daily. (c) six electric tubes of rating 18 W each for 6 hours daily. Calculate the electricity bill for the household for month of June if cost of electrical energy is Rs. 3.00 per unit.

Answer:

                  Energy consumed per day by refrigerator (Power of refrigerator          (1) Energy consumed per day by fans = 2 x 0.08 k W x 6  (Power of each (1)                                      = 0.9kWh Energy consumed by lights                                                          (1) Total energy consumed per day = 4 + 0.96 + 0.648 = 5.608 kWh Energy consumed in 30 days = 30 X 5.608 = 168.24 kWh                                         (1) Cost of 261.84 unit @ ` 3.00 = 168.24 X 3 =` 504.72                                             (1)