Answer:
(a)
Let us assume that the resistance of each bulb be R. The circuit diagram in two
cases may be drawn as given below
(1)
Equivalent resistance in series combination
Voltage = V
Let current through each bulb in series combination be . By Ohm's law,
Power consumption of each
bulb in series combination,
?(i)
(1)
For parallel circuit,
The resistance of each bulb = R
Voltage across each bulb = V
( same voltage in parallel
combination)
Power consumption of each
bulb in parallel combination ?(ii)
From equations (i) and (ii),
we have
Therefore, each bulb in parallel combination glows 3 times
brighter to that of each bulb in series combination.
(b) When one bulb gets fused in both the circuit, then in
series combination, circuit gets broken and current stops flowing whereas in
parallel combination, same voltage continue to act on the remaining voltage and
hence other bulbs continue to glow with same brightness. (2)
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