Answer:
In the solid state, higher enthalpy
of lattice formation by \[{{M}^{2+}}\] ions (as compared to \[{{M}^{+}}\] ions)
more than compensates the higher second ionization enthalpies of metals and in
aqueous solution, higher enthalpy of hydration of\[{{M}^{2+}}\] ions (as
compared to \[{{M}^{+}}\]ions) more than compensates the higher second
ionization enthalpy of metals.
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