Answer:
The lattice enthalpy of \[BaS{{O}_{4}}\]
is much more than its hydration enthalpy and hence it is insoluble in water. But
hydration enthalpy of \[BeS{{O}_{4}}\] is much higher than its lattice enthalpy
because of small size of \[B{{e}^{2+}}\] ions. Therefore, it is highly soluble
in water.
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