Answer:
Upon heating, \[L{{i}_{2}}C{{O}_{3}}\]
forms \[L{{i}_{2}}O\] and \[C{{O}_{2}}\]. On the other hand, \[N{{a}_{2}}C{{O}_{3}}\]
upon heating is expected to form\[N{{a}_{2}}O\] and\[C{{O}_{2}}\]. Since the
size of \[L{{i}^{+}}\] ion is smaller as compared to that of \[N{{a}^{+}}\] ion
therefore, the crystal lattice of \[L{{i}_{2}}O\] is thermally more stable than
that of \[N{{a}_{2}}O.\] \[L{{i}_{2}}C{{O}_{3}}\] therefore, decomposes upon
heating to form lithium oxide (stable oxide). \[N{{a}_{2}}C{{O}_{3}}\] does not
decompose on heating since \[N{{a}_{2}}O\] is less stable.
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