Answer:
(i) \[N{{H}_{3}}(107{}^\circ
)>{{H}_{2}}O>(104.5{}^\circ ).\]
(ii)\[NH_{4}^{+}>N{{H}_{3}}>NH_{2}^{-}\]
This
is because all of them involve\[s{{p}^{3}}\] hybridization. The number of lone
pair of electrons present on N-atom are 0, 1 and 2 respectively. Greater the
number of lone pairs, greater are the repulsions on the bond pairs and hence
smaller is the angle.
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