Answer:
\[\underset{Styrene}{\mathop{{{C}_{6}}{{H}_{5}}CH=C{{H}_{2}}}}\,\xrightarrow{B{{r}_{2}}}\,\underset{\begin{smallmatrix}
\,\,\,\,\,\,\,\,\,\,\text{1,}\,\text{2-Dibromo-}\,
\\
\text{1-phenylethane}\,\text{(A)}
\end{smallmatrix}}{\mathop{{{C}_{6}}{{H}_{5}}-\underset{\begin{smallmatrix}
| \\
Br
\end{smallmatrix}}{\mathop{C}}\,H-\underset{\begin{smallmatrix}
| \\
Br
\end{smallmatrix}}{\mathop{C}}\,{{H}_{2}}}}\,\]\[\xrightarrow[(-2\,HBr)]{2\,NaN{{H}_{2}}}\,\underset{\text{Phenylacetylene}}{\mathop{{{C}_{6}}{{H}_{5}}-C\equiv
CH}}\,\]
Thus, [A] is 1, 2-dibromo 1-phenylethane
and [B] is 1-phenylpropyne.
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