Answer:
\[pH\] of water will be different at these temperatures.
Rather \[pH\] of \[4{}^\circ C\]will be more than\[pH\] at \[25{}^\circ C\]. Actually, for water (neutral):
\[[{{H}^{+}}]\times [O{{H}^{-}}]={{K}_{w}}={{10}^{-14}}\] at \[25{}^\circ C\] Similarly, \[pH\times pOH=p{{K}_{w}}=14\] at \[25{}^\circ C\]
or \[pH=pOH\,=7\] (\[\because \] Water is neutral and\[pH=pOH\])
On increasing the temperature, dissociation of water increases and so is the value of \[{{K}_{w}}\]. This means that at lower temperature (say \[4{}^\circ C\]), the value of \[{{K}_{w}}\] will decrease or\[p{{K}_{w}}\] will be more than 14. This also means that at lower temperature, the value of \[pH\] (or\[pOH\] ) will be more than 7.
You need to login to perform this action.
You will be redirected in
3 sec