Answer:
This is done to convert \[N{{H}_{4}}HC{{O}_{3}}\] usually present in large amounts along with \[{{(N{{H}_{4}})}_{2}}C{{O}_{3}}\] to \[{{(N{{H}_{4}})}_{2}}C{{O}_{3}}\]
\[N{{H}_{4}}HC{{O}_{3}}\,+N{{H}_{4}}OH\xrightarrow{\,}\,{{(N{{H}_{4}})}_{2}}C{{O}_{3}}+{{H}_{2}}O\]
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