Answer:
(i) \[{{H}_{3}}{{O}^{+}},\,O{{H}^{-}}\] (ii) \[{{H}_{2}}S{{O}_{4}},\,SO_{4}^{2-}\]
(iii) \[NH_{4}^{+},\,NH_{2}^{-}\] (iv) \[{{H}_{2}}S,\,{{S}^{2-}}\]
Note. To write the conjugate acid of the given species, add \[{{H}^{+}}\] ion. To write the conjugate base of the given species, subtract \[{{H}^{+}}\] ion.
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