Answer:
(a) Let us write the oxidation numbers of all the atoms of the reactants and products taking part in the reaction.
\[C{{H}_{4}}\] is reductant (reducing agent) and \[C{{l}_{2}}\] is oxidant (oxidising agent).
(b) Let us write the oxidation numbers of all the atoms of the reactants and products taking part in the reaction.
\[{{C}_{2}}{{H}_{2}}{{O}_{4}}\]is reductant (reducing agent) and \[Mn{{O}_{2}}\] is oxidant (oxidising agent).
(c) Let us write the oxidation numbers of all the atoms of the reactants and products taking part in the reaction.
\[{{S}_{2}}{{O}_{3}}^{2-}\] is reductant (reducing agent) and \[{{I}_{2}}\] is oxidant (oxidising agent).
(d) Let us write the oxidation numbers of atoms of all the reactants and products taking part in the reaction.
\[B{{r}^{-}}\] is reductant (reducing agent) and \[C{{I}_{2}}\] is oxidant (oxidising agent).
You need to login to perform this action.
You will be redirected in
3 sec