Answer:
Boron can show a maximum valency as
well as co-ordination number of four. Therefore, it cannot form \[{{[B{{F}_{6}}]}^{3-}}\]
ion where it is to exhibit co-ordination number six. On the other hand, aluminium
can extend its valency as well as co-ordination number to six due to the
presence of vacant 3d orbitals. Therefore, it can form \[{{[Al{{F}_{6}}]}^{3-}}\]
ion.
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