Answer:
Boron has three electrons in the
valence shell. Because of its small size and high sum of the first three
ionization enthalpies (i.e., \[{{\Delta }_{i}}{{H}_{1}}+{{\Delta
}_{i}}{{H}_{2}}+{{\Delta }_{i}}{{H}_{3}}),\] boron does not lose all its
valence electrons to form \[{{B}^{3+}}\] ions.
You need to login to perform this action.
You will be redirected in
3 sec