Answer:
Here, radius of proton,
\[{{\text{y}}_{\text{1}}}=\text{
1}{{0}^{-\text{9}}}\text{micron }=\text{1}{{0}^{-\text{15}}}\text{m}\]
. and radius of universe,
\[{{\text{y}}_{\text{2}}}=\text{1}{{0}^{\text{28}}}\text{cm
}=\text{ 1}{{0}^{\text{26}}}\text{m}\]
The size y, half way between these two on a logarithmic scale is
\[\text{log y }=\frac{\log {{y}_{1}}+\log
{{y}_{2}}}{2}=\frac{\log {{10}^{-15}}+\log
{{10}^{26}}}{2}=\frac{-15+26}{2}=\frac{11}{2}=5.5\approx 6\]
\[\therefore\]
\[\text{y}=\text{
1}{{0}^{\text{6}}}\text{metre}\]
This is the order of size of earth. Hence the physical object is
earth.
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