Answer:
Length (l)
Least count
\[\left( \Delta l \right)\]
Relativeerro
\[\left( \frac{\Delta l}{l} \right)\]
(i)
4.0 M
0.01mm
\[\frac{0.01}{4.00}=\text{2}.\text{5}\times
\text{1}{{0}^{-\text{3}}}\]
(ii)
4.0 M
0.01 cm
\[\frac{0.01}{4.00}=\text{2}.\text{5}\times
\text{1}{{0}^{-\text{3}}}\]
(iii)
4.0
M
0.01 m
\[\frac{0.01}{4.00}=\text{2}.\text{5}\times
\text{1}{{0}^{-\text{3}}}\]
(iv)
40.00
M
0.01m
\[\frac{0.01}{40.00}=\text{2}.\text{5}\times
\text{1}{{0}^{-4}}\]
As relative error in measurement of 40.00 m is minimum, therefore,
it is most accurate measurement. However, the least count of measuring
instrument is minimum in case (i) being equal to 0.01 mm. Therefore,
measurement (i) is most precise.
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