Answer:
\[\text{Q}=\text{CV}=\text{2}.0\times
\text{2}0=\text{4}0\]micro coulomb = \[\text{4}0\times
\text{1}{{0}^{-\text{6}}}\text{ C}\]
\[\frac{\Delta
Q}{Q}=\frac{\Delta C}{C}+\frac{\Delta
V}{V}=\frac{0.1}{2.0}+\frac{0.5}{20}=\frac{3}{40}\]
\[\Delta
Q=\frac{3}{40}\times Q=3.0\mu C\] Hence, \[Q=\left( 40\pm 3.0 \right)\times
{{10}^{-6}}C\]
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