Answer:
From \[X=\text{ 3}Y{{Z}^{2}}\]
\[Y=\text{ }\frac{\text{X}}{\text{3}{{Z}^{2}}}=\frac{capaci\tan ce}{{{\left( mag.\,induction \right)}^{2}}}=\frac{{{M}^{-1}}{{L}^{-2}}{{T}^{2}}{{Q}^{2}}}{\left[ M{{T}^{-1}}{{Q}^{-1}} \right]}=\left[ {{M}^{-3}}{{L}^{-2}}{{T}^{4}}{{Q}^{4}} \right]\]
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