Answer:
As \[C=\frac{{{\in
}_{0}}A}{d}\] and \[\rho =\frac{RA}{l}\], where the symbols have their usual
meaning, therefore,
\[\frac{CV}{\rho {{\in }_{0}}}=\left( \frac{{{\in }_{0}}A}{d}
\right)\frac{V}{\left( RA/l \right){{\in }_{0}}}=\frac{V}{R}=I\], the current (\[\because
\]\[l\],\[d\] both represent distance)
Therefore, the quantity
represented is current.
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