Answer:
Here, OA
=R, \[\angle AOC=\theta \]
Block moves in a horizontal circle with centre
C and radius \[r=AC=R\sin \theta \], Fig.
3(HT). 10.
\[\therefore \] In equilibrium,
\[~\text{Ncos}\theta =\text{mg}\] ...(i)
and \[\text{Nsin}\theta =\text{m}{{\omega
}^{\text{2}}}(\text{R}\,\text{sin}\theta )\]
\[N=m{{\omega
}^{2}}R\]
From (i) \[m{{\omega }^{2}}R\cos \theta
=mg\]
\[\omega
=\sqrt{\frac{g}{R\cos \theta }}\]
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