Answer:
(a) As
the boy does not slide back, its acceleration = ace. of the horse.
As friction is the only horizontal force, it
must act along the acceleration.
\[\therefore \] \[{{f}_{s}}=M\,\,a=30\left( 2.0
\right)=60N\].
(b) If the boy slides back, the horse could not exert a
friction of 60 N on the boy.
Maximum force of static friction
\[{{f}_{s}}={{\mu }_{s}}R={{\mu }_{s}}\left( M\,g
\right)\]
\[\therefore \] \[{{\mu }_{s}}\left( 30 \right)\left( 10
\right)\le 60N\]
\[\therefore \] Max. value of coeff. of static friction \[={{\mu
}_{s}}=\frac{60}{300}=0.20\]
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