Answer:
If a is the common acceleration, then
\[F=3M\times a\] or \[a=\frac{F}{3M}\]
Net force on block A, \[{{F}_{1}}=3M\times
a=3M\times \frac{F}{3M}=F\]
Force applied by A on
B, \[{{F}_{2}}=(M+M)a=2M\times \frac{F}{3M}=\frac{2F}{3}\]
Force applied by B on C
\[{{F}_{3}}=M+a=M\times \frac{F}{3M}=F/3\]
The action reaction
forces are shown in Fig. 3(a).26.
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