Answer:
Limiting
force of friction \[F=\mu R=\mu mg\,=0.6\,\times 1\times 9.8=5.88\,N\]
Applied force, \[F'=ma\,=1\times 5=5N\]
As \[F'<F\], the block would not move.
Force of friction = applied force = 5 N.
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