Answer:
From\[{{F}_{1}}=\frac{dP}{d{{t}_{1}}}\]
and \[{{F}_{2}}=\frac{dP}{d{{t}_{2}}}\]
\[\frac{{{F}_{2}}}{{{F}_{1}}}=\frac{d{{t}_{1}}}{d{{t}_{2}}}\]; \[{{F}_{2}}={{F}_{1}}\times
\frac{d{{t}_{1}}}{d{{t}_{2}}}=\frac{5\times 5}{2}=12.5N\]
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