Answer:
Let r be the radius of semicircular
path. Here, \[l=\left( \text{2}\pi \text{ r}/\text{2} \right)\]
or
\[\text{r}=\text{l}/\pi \].
Diameter
=\[\text{2r}=\text{2}\,\text{l}/\pi \]; Magnitude of displacement = diameter \[=\text{2}\,\text{l}/\pi
\]
\[\frac{Dis\tan ce}{Displacement}=\frac{l}{2l/\pi
}=\frac{\pi }{2}\]
You need to login to perform this action.
You will be redirected in
3 sec