Answer:
Given, \[\text{x}\propto {{\text{t}}^{\text{2}}}\]or \[\text{x}=\text{k}{{\text{t}}^{\text{2}}}\]where
k is a constant of proportionality.
speed/velocity of the particle, \[v=\frac{dx}{dt}=\frac{d}{dt}(k{{t}^{2}})\]=
2kt ...(i)
and acceleration of the particle, a = \[\frac{dv}{dt}=\frac{d}{dt}\]
(2kt) = 2k ....(ii)
From (i) and (it) we note that acceleration of the particle
is constant whereas the velocity of the particle depends upon the time.
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