Answer:
If\[\theta
\] is the angle between \[\vec{A}\]and \[\vec{B}\],
Then
\[C={{\left( {{A}^{2}}+{{B}^{2}}+2AB\cos \theta \right)}^{1/2}}=\left( A+B
\right)\] [Given]
\[\therefore
\] \[{{A}^{2}}+{{B}^{2}}+2AB\cos \theta ={{\left( A+B \right)}^{2}}={{A}^{2}}+2AB+{{B}^{2}}\]
or \[\cos
\theta =1\] or \[\theta
={{0}^{o}}\]
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